Posted On:February 1, 2019, Posted By: Latest Interview Questions,
Views: 251, Rating :

Dear Readers, Welcome to __ THEORY of STRUCTURES Interview Questions and Answers__ have been designed specially to get you acquainted with the nature of questions you may encounter during your Job interview for the subject of

A. Both the ends are fixed

B. Both the ends are hinged

C. One end is fixed and other end is free

D. One end is fixed and other end is hinged

ANS: A

A. The structural member subjected to compression and whose dimensions are small as

B. compared to its length, is called a stmt

The vertical compression members are generally known as columns or stanchions

C. Deflection in lateral direction of a long column, is generally known as buckling

D. All the above

ANS: D

A. Straight line formula

B. Parabolic formula

C. Perry’s formula

D. Rankine’s formula

ANS: B

A. Guest’s or Trecas’ theory

B. St. Venant’s theory

C. Rankine’s theory

D. Von Mises’ theory

ANS: C

A. The moment of inertia is calculated about the axis about which bending takes place

B. If tensile stress is less than axial stress, the section experiences compressive stress

C. If tensile stress is equal to axial stress, the section experiences compressive stress

D. All the above

ANS: D

A. Steel experiences tensile force

B. Brass experiences compressive force

C. Composite beam gets subjected to a couple

D. All the above

ANS: D

A. Maximum bending stress = 32M d3

B. Maximum shear stress = 16 T d3

C. Both A. and B.

D. Neither A. nor B.

ANS: C

A. /4h thrust is

B. /8h

C. /12h

D. /16h

ANS: D

A. A uniforml 4/3

B. end, is

C. All the above

ANS: C

A. Guest’s or Trecas’ theory

B. St. Venant’s theory

C. Rankine’s theory

D. Haig’s theory

ANS: B

A. Area of cross-section divided by radius of gyration

B. Area of cross-section divided by least radius of gyration

C. Radius of gyration divided by area of cross-section

D. Length of column divided by least radius of gyration

ANS: D

A. It is subjected to pure bending

B. Its mean diameter will decrease

C. Its number of coils will increase

D. All the above

ANS: A

A. 1/4

B. 1/2

C. 1

D. 2

ANS: D

A. Guest’s or Trecas’ theory

B. St. Venant’s theory

C. Rankine’s theory

D. Haig’s theory

ANS: A

A. ML/EI

B. ML/2EI

C. ML²/2EI

D. ML²/3EI

ANS: D

A. For channels, the shear centre does not coincide its centroid

B. The point of intersection of the bending axis with the cross section of the beam, is called shear centre

C. For I sections, the shear centre coincides with the centroid of the cross section of the beam

D. All the above

ANS: D

A. Horizontal thrust is wl2/8h

B. S.F. will be zero throughout

C. B.M. will be zero throughout

D. All the above

ANS: D

A. 3.0 t compression

B. 3.0 t tension

C. t tension

D. t compression

ANS: C

A. Both the ends are fixed

B. Both the ends are hinged

C. One end is fixed and other end is free

D. One end is fixed and other end is hinged

ANS: B

A. Zero

B. 1

C. 2

D. 3

ANS: B

A. Graphical method

B. Method of joints

C. Method of sections

D. All the above

ANS: D

A. 2/3

B. 3/2

C. 5/8

D. 8/5

ANS: D

A. E = /A. L

B. E =/P. L

C. E = P. L/

D. E = P. A/ ANS: C

A. L/2

B. L/3

C. L/4

D. L/5

ANS: D

A. The outer most fibre of the section

B. The inner most fibre of the section

C. The neutral fibre of the section

D. The fibre everywhere

ANS: A

A. (IX + IY)/2

B. (IX – IY)/2

C. IX + IY

D. (I /I )

ANS: C

A. wa/27

B. wa²/27

C. w²a

D. wa²

ANS: D

A. E = 3K (1 – 2/m)

B. E = 2N (1 + 1/m)

C. (3/2)K (1 – 2/m) = N (1 + 1/m)

D. All the above

ANS: D

A. Compressive stress

B. Tensile stress

C. Shear stress

D. None of these

ANS: C

A. Magnitude

B. Direction

C. Point of application

D. All the above

ANS: D

A. It moves horizontally

B. It moves vertically

C. It rotates about its C.G.

D. None of these

ANS: D

A. Modulus of rigidity

B. Angle of twist

C. Reciprocal of the length of the shaft

D. Moment of inertia of the shaft section

ANS: D

A. Compressive stress

B. Tensile stress

C. Shear stress

D. None of these

ANS: B

A. ½

B. 1

C. 1½

D. 2

ANS: D

A. Stiffness

B. Proof resilience

C. Proof stress

D. Proof load

ANS: A

A. b = 10 N/mm2 s = 20 N/mm 2

B. b = 8 N/mm2 s = 16 N/mm2

C. b = 6 N/mm2 s = 12 N/mm2

D. b = 5 N/mm2 s = 10 N/mm2

ANS: A

A. 4WD²n/d4N

B. 4W²Dn/d4N

C. 4W²D3n/d4N

D. 4W²D3n²/d4N

ANS: C

A. 1

B. 2

C. 3

D. Zero ANS: C

A. bh²/12

B. b²h/12

C. bh3/12

D. b3h/12

ANS: C

A. Material is homogeneous

B. Material is isotropic

C. Young’s modulus is same in tension as well as in compression

D. All the above

ANS: D

A. Joint C

B. Joint B

C. Joint D

D. Joint A

ANS: C

A. 1

B. 2

C. 3

D. 4

ANS: D

A. 4.0 mm

B. 4.5 mm

C. 5.0 mm

D. 5.5 mm

ANS: C

A. wl3/3EI

B. wl4/3EI

C. wl4/8EI

D. wl4/12EI

ANS: C

A. Two bars

B. Three bars

C. Three parallel bars

D. Three bars intersecting at a point

ANS: B

A. Compressive stress

B. Tensile stress

C. Shear stress

D. None of these

ANS: A

A. 25 N

B. 30 N

C. 35 N

D. 40 N

ANS: C

A. 0.001

B. 0.002

C. 0.0025

D. 0.003

ANS: C

A. Stiffness

B. Proof resilience

C. Proof stress

D. Proof load

ANS: B

A. A joint

B. B joint

C. C joint

D. D joint

ANS: C

A. Is directly proportional to the volume

B. Is directly proportional to the square of exerted pressure

C. Is inversely proportional to Bulk modulus

D. All the above

ANS: D

A. L/d

B. L/2d

C. (L/2d)²

D. (L/3d)²

ANS: C

A. 0.207

B. 0.307

C. 0.407

D. 0.508

ANS: A

A. 100 t compressive

B. 100 t tensile

C. Zero

D. Indeterminate

ANS: C

A. A wire wound in spiral form, is called a helical spring

B. The pitch of a close coil spring, is very small

C. The angle made by the coil with horizontal, is called the angle of helix

D. All the above

ANS: D

A. Yield ratio

B. Hooke’s ratio

C. Poisson’s ratio

D. Plastic ratio

ANS: C

A. 2/3

B. 3/2

C. 8/5

D. 5/8

ANS: C

A. 4t tension

B. 4t compression

C. 4.5t tension

D. 4.5t compression

ANS: D

Q No: 65

For beams breadth is constant,

A. Depth d M

B. Depth d 3

C. Depth d

D. Depth d 1/M

ANS: B

A. 2/3

B. 3/2

C. 3/4

D. 4/3

ANS: D

A. Straight line formula

B. Parabolic formula

C. Perry’s formula

D. Rankine’s formula

ANS: D

A. In a loaded beam, the moment at which the first yield occurs is called yield moment

B. In a loaded beam, the moment at which the entire section of the beam becomes fully plastic, is called plastic moment

C. In a fully plastic stage of the beam, the neutral axis divides the section in two sections of equal area

D. All the above

ANS: D

A. 0.303

B. 0.404

C. 0.505

D. 0.707

ANS: D

A. Mcg = M M2 + r2) where letters carry their usual meanings

B. Tcp = m2 + T2)where letters carry their usual meanings

C. The torque which when acting alone would produce maximum shear stress equal to the maximum shear stress caused by the combined bending and torsion, is called equivalent torque

D. All the above

ANS: D

A. m = m1 + m2

B. m = m1 + m2 + 1

C. m = m1 + m2 + 2

D. m = m + m + 3

ANS: D

A. l/4

B. h/4

C. l

D. l

ANS: C

A. Stiffness

B. Proof resilience

C. Proof stress

D. Proof load

ANS: D

A. 5t tension

B. 4t tension

C. 4t compression

D. 5t compression

ANS: B

A. WL/2AE

B. WL/AE

C. W²L/AE

D. W²L/2AE

ANS: D

A. WI/2

B. WI²/4

C. WI²/8

D. WI²/12

ANS: C

A. Wa/h

B. Wa/2h

C. 2W/ha

D. 2h/Wa

ANS: B

A. 3t compression

B. 3t tension

C. Zero

D. 1.5t compression

ANS: C

A. Depth of the section

B. Depth of the neutral axis

C. Maximum tensile stress at the section

D. Maximum compressive stress at the section

ANS: B

A. 4

B. 8

C. 12

D. 16

ANS: D

A. 1

B. 1.25

C. 1.5

D. 2.5

ANS: C

A. 100 t compressive

B. 100 t tensile

C. Zero

D. Indeterminate

ANS: C

A. 264 MN

B. 274 MN

C. 284 MN

D. 294 MN

ANS: C

A. 1.4

B. 1.5

C. 1.6

D. 1.7

ANS: B

A. 75 N/m2

B. 750 N/m 2

C. 7500 N/m 2

D. 75000 N/m2

ANS: C

A. It regains its original shape on removal of the load

B. It regains its original shape partially on removal of the load

C. It does not regain its original shape at all

D. None of these

ANS: A

A. /30 Newton metres/sec

B. /30 Newton metres/min

C. /60 Newton metres/min

D. /60 Newton metres/sec

ANS: A

A. Q = S + F

B. Q = S – F

C. Q = F – S

D. Q = S × F

ANS: D

A. WL²/2EI

B. WL²/3EI

C. WL3/2EI

D. WL3/3EI

ANS: D

A. For a uniformly distributed load, the shear force varies linearly

B. For a uniformly distributed load, B.M. curve is a parabola

C. For a load varying linearly, the shear force curve is a parabola

D. All the above

ANS: D

A. 1/2

B. 2/3

C. 1/4

D. 1/3

ANS: B

A. 200 mm

B. 250 mm

C. 300 mm

D. 400 mm

ANS: D

A. Zero

B. 5t tension

C. 5t compression

D. 4t tension

ANS: C

A. (1/3) A

B. (1/6) A

C. (1/12) A

D. (1/18) A

ANS: D

A. D4 – d4)

B. D4 – d4)

C. D4 – d4)

D. D4 – d4)

ANS: D

A. 4.0t compression

B. 3.0t compression

C. 0.5t compression

D. 0.5t tension ANS: C

A. 2 L

B. L

C. L/2

D. L

ANS: D

A. Supporting reactions only

B. Shear forces only

C. Bending moments only

D. All the above

ANS: D

A. [W (1 + f/ G)]/ A

B. (1 – g/f)/A

C. [W (2 + f/G)]/A

D. [W (2 + g/f)]/A

ANS: A

** THEORY of STRUCTURES Objective Questions Pdf Download ::**

A. 1/2

B. 1/3

C. 2/3

D. 3/2

ANS: C