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A generator is a machine which converts mechanical energy to electrical energy.
An AC generator is also called an alternator.
f=n∗p120=1200∗6120=60Hzf=n∗p120=1200∗6120=60Hz
n=120∗fp=120∗608=900RPMn=120∗fp=120∗608=900RPM
The standard frequency in North America is 60 Hz
Vp=2–√Vrms=1.414∗240=339VVp=2Vrms=1.414∗240=339V
1. Determine the peak value of this voltage.
Vp=2–√Vrms=1.414∗10=14.14VVp=2Vrms=1.414∗10=14.14V
2. Determine the RMS value of this voltage.
Measured voltage is RMS voltage; 10-V rms.
3. Determine the peak to peak value of this voltage.
Peak x 2 = peak to peak; 14.14 x 2 = 28.28 volts peak to peak.
120-V and 240-V AC
By interchanging the supply phases the motor will run in reverse.
1.The phase sequence or rotation of the machine must be the same as that of the system.
2.The alternator voltage must be in phase with the grid system.
3.The alternator frequency must be the same as the grid system frequency.
The stator coils must be set to 120 degrees apart.
The Wye and Delta connections.
The current and voltage are in phase.
1. The peak value of the voltage.
340-V/2 = 170-V peak
2. The effective value of the voltage.
1702√=120V1702=120V
3. The wattage.
120V/10? = 12Amps;
12A x 120V = 1440 Watts