Dear Readers, Welcome to Simple Interest - Aptitude Objective Questions have been designed specially to get you acquainted with the nature of questions you may encounter during your Job interview for the subject of Simple Interest - Aptitude MCQs. These objective type Simple Interest - Aptitude questions are very important for campus placement test and job interviews. As per my experience good interviewers hardly plan to ask any particular question during your Job interview and these model questions are asked in the online technical test and interview of many Banks, SSC, Railways, Postal and many Govt Jobs.
1. Principal :
The money borrowed or lent out for a certain period is called the principal or the sum.
2. Interest :
Extra money paid for using other’s money is called interest.
3. Simple Interest (S.I.) :
If the interest on a sum borrowed for certain period is reckoned uniformly, then it is called simple interest.
Let the principal = P, Rate = R% per annum (p.a) and Time = T years. Then ,
1. S.I. = (P x R x T / 100)
2. P = (100 x S.I. / R x T)
3. R = (100 x S.I / P x T)
4. T = (100 x S.I. / P x R).
Explanation:
Let principal = P. Then, S.I. = P and T = 16 years
=> Rate = [100 * P / P * 16]%
= 6 1/4% p.a
Explanation:
Let sum = Rs. x Then, S.I. = Rs. 4x/9
Let rate = R% and time = R years.
Then, [x * R * R / 100] = 4x / 9 or R² = 400/9 or R = 20/3 = 6 2/3
=> Rate = 6 2/3 % and Time = 6 2/3 yrs
= 6 yrs 8 months.
Explanation:
Let sum = P and original rate = R. Then,
[P * (R+2) * 3 / 100] - [P * R * 3 / 100] = 360
=> 7x/20 - 3x/10 = 40
=> x = (40 * 20) = 800.
Hence, the sum is Rs. 800.
Explanation:
Let sum = P and original rate = R. Then,
[P * (R+2) * 3 / 100] - [P * R * 3 / 100] = 360
=> 7x/20 - 3x/10 = 40
=> x = (40 * 20) = 800.
Hence, the sum is Rs. 800.
Explanation:
Let rate = R% and time = R years. Then
(1200 x R x R / 100) ‹=› 432
‹=›12R2 = 432
‹=›R2 = 36
‹=› R = 6
A. Rs. 150
B. Rs. 750
C. Rs. 700
D. Rs. 3250
Answer: B
Explanation:
2500 * (3 * (5/100)) =750
A.764
B.992
C.850
D.770
Answer: B
Explanation:
S.I = Rs. (920 – 800) = Rs. 120; P = Rs. 800, T = 3 yrs
R = ( 100 X 120 )% / 800 X 3 = = 5%
New rate = (5 + 3) % = 8%
New S.I. = Rs. (800 X 8 X 3)/ 100== Rs. 192.
New amount = Rs. (800 + 192) = Rs. 992
A.650
B.690
C.698
D.700
Answer: C
Explanation:
S.I. for 1 year = Rs. (854 – 815) = Rs. 39
S.I. for 3 years = Rs. (39 x 3) = Rs. 117
Principle = Rs. (815 – 117) = Rs. 698
A.1050
B.2050
C.3000
D.5000
E.None of these
Answer: E
Explanation:
Money paid in cash = Rs. 1000.
Balance payment = Rs. (20000 – 1000)
= Rs. 19000.
A.200
B.240
C.250
D.300
Answer:C
Explanation:
Let the Principal be P Rs.
Let the first rate of interest be r
The difference in r is 5
5 x P x N = (Difference in interest) x 100
5 x P x 8 = 100 x 100
p = 100 x 100 / 5 x 8
= Rs. 250
A.1190
B.1120
C.1210
D.1280
Answer: B
Explanation:
Let the required sum of money be Rs. X.
Here R1 = 5%, T1 = 4 years, R2 = 4%, T2 = 10 years.
Given X : 560 = 1 / R1T1 : 1 / R2T2 :
= 1 / 5X4 : 1 / 4X10
X = 2 or, X = Rs. 1120.
A. 8925
B. 8259
C. 8529
D. 8952
Ans: A
Explanation:
Principal = Rs. [100 * 4016.25 / 9 * 5]
= Rs. [401625 / 45]
= Rs. 8925.
A. 500
B. 698
C. 780
D. 910
Ans: B
Explanation:
S.I. for 1 year = Rs. (854 - 815) = Rs. 39.
S.I. for 3 years = Rs. (39 * 3) = Rs. 117.
Principal = Rs. (815 - 117)
= Rs. 698.
A. 6 years
B. 7 years
C. 8 years
D. 9 years
Ans: C
Explanation:
Let the sum be x. Then, S.I. = 40% of x = 2x/5; Rate = 5%.
Time = [100 * 2x/5 * 1/x*5]
= 8 years.
A. Rs. 500
B. Rs. 600
C. Rs. 700
D. Rs. 710
Ans: B
Explanation:
S.I. for 5 year = Rs.(1020 - 720)
= Rs. 300.
S.I. for 2 year = Rs.(300/5×2)
= Rs. 120.
Principal = Rs. (720 - 120)
= Rs. 600.
A. 3.5 years
B. 4 years
C. 4.5 years
D. 5 years
Ans: B
Explanation:
Time = (100×81/ 450×4.5)years
= 4 years.
A. 3%
B. 4%
C. 5%
D. 6%
Answer: D
Explanation:
S.I. = Rs. (15500 - 12500) = Rs. 3000.
Rate = (100 x 3000/12500 x 4)% = 6%