Dear Readers, Welcome to Transformer Objective Questions and Answers have been designed specially to get you acquainted with the nature of questions you may encounter during your Job interview for the subject of Transformer Multiple choice Questions. These objective type Transformer Questions are very important for campus placement test and job interviews. As per my experience good interviewers hardly plan to ask any particular question during your Job interview and these model questions are asked in the online technical test and interview of many IT & Non IT Industries.
(a) Current
(b) Voltage
(c) Frequency
(d) All of the above
Ans: c
(a) through cooling coil
(b) through air
(c) by the flux
(d) none of the above
Ans: c
(a) reduce hysteresis loss
(b) reduce eddy current losses
(c) reduce copper losses
(d) reduce all above losses
Ans: b
(a) tightness of clamping
(b) gauge of laminations
(c) size of laminations
(d) all of the above
Ans: d
(a) 0.2 to 0.5 per cent
(b) 2 to 5 per cent
(c) 12 to 15 per cent
(d) 20 to 30 per cent
Ans: b
(a) high resistance
(b) high reluctance
(c) low resistance
(d) low reluctance
Ans: d
(a) copper loss
(b) magnetising current
(c) magnetising current and loss
(d) efficiency of the transformer
Ans: c
(a) lkV
(b) 33 kV
(c) 100 kV
(d) 330 kV
Ans: b
(a) temperature
(b) stray losses
(c) all-day efficiency
(d) none of the above
Ans: a
(a) 1.7 Wb/m2
(b) 2.7 Wb/m2
(c) 3.7 Wb/m2
(d) 4.7 Wb/m2
Ans: a
(a) copper losses = hysteresis losses
(b) hysteresis losses = eddy current losses
(c) eddy current losses = copper losses
(d) copper losses = iron losses
Ans: d
(a) lags behind the voltage by about 75°
(b) leads the voltage by about 75°
(c) lags behind the voltage by about 15°
(d) leads the voltage by about 15°
Ans: a
(a) provide support to windings
(b) reduce hysteresis loss
(c) decrease the reluctance of the magnetic path
(d) reduce eddy current losses
Ans: c
(a) Conservator
(b) Breather
(c) Buchholz relay
(d) Exciter
Ans: d
(a) High voltage side
(b) Low voltage side
(c) Primary side
(d) Secondary side
Ans: b
(a) Low voltage winding
(b) High voltage winding
(c) Primary winding
(d) Secondary winding
Ans: a
(a) voltage
(b) current
(c) power
(d) frequency
Ans: c
(a) there is no need to change the D.C. voltage
(b) a D.C. circuit has more losses
(c) Faraday's laws of electromagnetic induction are not valid since the rate of change of flux is zero
(d) none of the above
Ans: c
(a) is always a low voltage winding
(b) is always a high voltage winding
(c) could either be a low voltage or high voltage winding
(d) none of the above
Ans: c
(a) Low voltage winding
(b) High voltage winding
(c) Primary winding
(d) Secondary winding
Ans: b
(a) 100 percent
(b) 98 percent
(c) 50 percent
(d) 25 percent
Ans: b
(a) friction and windage losses
(b) copper losses
(c) hysteresis and eddy current losses
(d) none of the above
Ans: c
(a) natural air cooling
(b) air blast cooling
(c) oil cooling
(d) any of the above
Ans: c
(a) 180°
(b) 120°
(c) 90°
(d) 75°
Ans: d
(a) supply frequency
(b) load current
(c) power factor of load
(d) both (b) and (c)
Ans: d
(a) provide fresh air for cooling the transformer
(b) supply cooling oil to transformer in time of need
(c) protect the transformer from damage when oil expends due to heating
(d) none of the above
Ans: c
(a) 3000 kVA
(b) 1000 kVA
(c) 500 kVA
(d) 250 kVA
Ans: a
(a) nearly full load
(b) 70% full load
(c) 50% full load
(d) no load
Ans: a
(a) at no load
(b) at 50% full load
(c) at 80% full load
(d) at full load
Ans: b
(a) load on it increases
(b) load on it decreases
(c) load remains constant
(d) none of the above
Ans: b
(a) has high magnitude and low power factor
(b) has high magnitude and high power factor
(c) has small magnitude and high power factor
(d) has small magnitude and low power factor
Ans: d
(a) to provide free passage to the cool¬ing oil
(b) to insulate the coils from each other
(c) both (a) and (b)
(d) none of the above
Ans: a
(a) less will be the secondary induced e.m.f.
(b) less will be the primary induced e.m.f.
(c) less will be the primary terminal voltage
(d) none of the above
Ans: a
(a) to provide coupling between primary and secondary
(b) to increase the magnitude of mutual flux
(c) to decrease the magnitude of mag-netizing current
(d) to provide all above features
Ans: c
(a) voltage device
(b) current device
(c) power device
(d) main flux device
Ans: d
(a) leakage reactance
(b) per unit impedance
(c) efficiencies
(d) ratings
Ans: b
(a) R2/VK
(b) R2IK2
(c) R22!K2
(d) R22/K
Ans: b
(a) The power factor of the two trans-formers will be different from the power factor of common load
(b) Incorrect polarity will result in dead short circuit
(c) The transformers will not share load in proportion to their kVA ratings
(d) none of the above
Ans: b
(a) transformers will be overheated
(b) power factors of both the trans-formers will be same
(c) parallel operation will be not possible
(d) parallel operation will still be possible, but the power factors at which the two transformers operate will be different from the power factor of the common load
Ans: d
(a) primary side
(b) secondary side
(c) low voltage side
(d) high voltage side
Ans: c
(a) reduces weight per kVA
(6) reduces iron losses
(c) reduces copper losses
(d) increases part load efficiency
Ans: a
(a) ionizing air
(b) absorbing moisture
(c) cleansing the transformer oil
(d) cooling the transformer oil.
Ans: b
(a) asbestos fibre
(b) silica sand
(c) sodium chloride
(d) silica gel
Ans: d
(a) true
(b) false
Ans: b
(a) volts
(b) amperes
(c) kW
(d) kVA
Ans: d
(a) magnetostrication
(b) boo
(c) hum
(d) zoom
Ans: c
(a) Bmax
(b) Bmax1-6
(C) Bmax1-83
(d) B max
Ans: b
(a) wood
(b) copper
(c) aluminium
(d) silicon steel
Ans: d
(a) 0.4 mm to 0.5 mm
(b) 4 mm to 5 mm
(c) 14 mm to 15 mm
(d) 25 mm to 40 mm
Ans: a
(a) to project against'internal fault
(b) to reduce copper as well as core losses
(c) to cool the transformer oil
(d) to take care of the expansion and contraction of transformer oil due to variation of temperature of sur-roundings
Ans: d
(a) 33 kV.
(6) 66 kV
(c) 132 kV
(d) 400 kV
Ans: d
(a) zero
(b) 1 ohm
(c) 1000 ohms
(d) infinite
Ans: d
(a) sludge
(b) odour
(c) gases
(d) moisture
Ans: d
(a) auto-transformers
(b) air-cooled transformers
(c) welding transformers
(d) oil cooled transformers
Ans: d
(a) 50°C
(b) 80°C
(c) 100°C
(d) 150°C
Ans: d
(a) fluctuating load
(b) poor insulation
(c) mechanical vibrations
(d) saturation of core
Ans: d
(a) 90% load
(b) zero load
(c) 25% load
(d) 50% load
Ans: d
(a) Mechanical strength
(6) Low hysteresis loss
(c) High thermal conductivity
(d) High permeability
Ans: c
(a) load is unbalanced only
(b) load is balanced only
(c) on balanced as well as unbalanced loads
(d) none of the above
Ans: b
(a) load is balanced only
(b) load is unbalanced only
(c) on balanced as well as unbalanced loads
(d) none of the above
Ans: c
(a) electrical fault inside the transformer itself
(b) electrical fault outside the transformer in outgoing feeder
(c) for both outside and inside faults
(d) none of the above
Ans: a
(a) small air gap
(b) large leakage flux
(c) laminated silicon steel core
(d) fewer rotating parts
Ans: a
(a) Frequency
(b) Voltage
(c) Current
(d) Any of the above
Ans: a
(a) Low hysteresis loss
(b) High permeability
(c) High thermal conductivity
(d) Adequate mechanical strength
Ans: c
(a) load current
(b) load current and voltage
(c) load current, voltage and frequency
(d) load current, voltage, frequency and power factor
Ans: a
(a) high reluctance
(b) low reactance
(c) high resistance
(d) low resistance
Ans: b
(a) special test
(b) routine test
(c) type test
(d) none of the above
Ans: c
(a) Core insulation voltage test
(b) Impedance test
(c) Radio interference test
(d) Polarity test
Ans: c
(a) leading power factor
(b) lagging power factor
(c) unity power factor
(d) zero power factor
Ans: a
(a) low voltage side of high kVA trans¬formers
(b) high frequency transformers
(c) high voltage side of small capacity transformers
(d) high voltage side of high kVA rating transformers
Ans: a
(a) increased core losses
(b) increased I2R losses
(c) magnetic interference with communication circuits
(d) all of the above
Ans: d
(a) copper core
(b) cost iron core
(c) air core
(d) mild steel core
Ans: c
(a) 6400 W
(b) 1600 W
(c) 800 W
(d) 400 W
Ans: d
(a) average value
(b) r.m.s. value
(c) maximum value
(d) instantaneous value
Ans: c
(a) hysteresis loss
(b) eddy current losses
(c) copper losses
(d) all of the above
Ans: a
(a) Primary winding
(b) Secondary winding
(c) Low voltage winding
(d) High voltage winding
Ans: d
(a) no-load
(b) half-load
(c) near full-load
(d) 10% overload
Ans: c
(a) Hysteresis losses are reduced
(b) Saving in winding material
(c) Copper losses are negligible
(d) Eddy losses are totally eliminated
Ans: b
(a) the current on secondary side is negligible
(b) the voltage on secondary side does not vary
(c) the voltage applied on primary side is low
(d) full-load current is not supplied to the transformer
Ans: c
(a) short-circuiting of the secondaries
(b) power factor of one of the trans¬formers is leading while that of the other lagging
(c) transformers having higher copper losses will have negligible core losses
(d) loading of the transformers not in proportion to their kVA ratings
Ans: d
(a) Conservator
(b) Breather
(c) Bushings
(d) Buchholz relay
Ans: a
(a) no losses and magnetic leakage
(b) interleaved primary and secondary windings
(c) a common core for its primary and secondary windings
(d) core of stainless steel and winding of pure copper metal
(e) none of the above
Ans: a
(a) flux density remains unaffected
(b) iron losses are reduced
(c) core flux density is reduced
(d) core flux density is increased
Ans: d
(a) value of transformation ratio remains constant
(b) permeability of transformer core remains constant
(c) core flux remains practically constant
(d) primary voltage remains constant
(c) secondary voltage remains constant
Ans: c
(a) copper loss = iron loss
(b) copper loss < iron loss
(c) copper loss > iron loss
(d) none of the above
Ans: a
(a) not change
(b) decrease
(c) increase
(d) any of the above
Ans: c
(a) capacitive only
(b) inductive only
(c) inductive or resistive
(d) none of the above
Ans: a
(a) low power factor wattmeter
(b) unity power factor wattmeter
(c) frequency meter
(d) any type of wattmeter
Ans: a
(a) hot because of heavy iron losses taking place in it due to high flux density
(b) hot because primary will carry heavy current
(c) cool as there is no secondary current
(d) none of above will happen
Ans: a
(a) mica strip
(6) thin coat of varnish
(c) paper
(d) any of the above
Ans: b
(a) Circular type
(b) Sandwich type
(c) Cylindrical type
(d) Rectangular type
Ans: b
(a) primary is supplied rated voltage
(b) primary is supplied full-load current
(c) primary is supplied current at reduced voltage
(d) primary is supplied rated kVA
Ans: a
(a) hysteresis losses
(b) copper losses
(c) core losses
(d) eddy current losses
Ans: c
(a) hysteresis losses
(b) copper losses
(c) core losses
(d) eddy current losses
Ans: b
(a) same efficiency
(b) same polarity
(c) same kVA rating
(d) same number of turns on the secondary side.
Ans: b
(a) low,low
(b) high,high
(c) low,high
(d) high,low
Ans: a
(a) to provide oxygen inside the tank
(b) to cool the coils during reduced load
(c) to cool the transformer oil
(d) to arrest flow of moisture when outside air enters the transformer
Ans: d
(a) Step-up transformer
(b) Step-down transformer
(c) Potential transformer
(d) Current transformer
Ans: d
(a) frequency
(b) area of the core
(c) flux density of the core material
(d) (a) and (b) both
Ans: d
(a) 1.5 MVA
(b) 5 MVA
(c) 15 MVA
(d) 50 MVA
Ans: a
(a) high eddy current losses
(b) reduced magnetic leakage
(c) negligibly hysteresis losses
(d) none of the above
Ans: b
(a) on full-load
(b) on overload
(c) on leading power factor
(d) on zero power factor
Ans: c
(a) voltage
(b) current
(c) current and voltage
(d) power
Ans: d
(a) llkV
(b) 33kV
(c) 66 kV
(d) 122 kV
Ans: d
(a) core built-up of laminations of cold rolled grain oriented steel
(b) core built-up of laminations of hot rolled sheet
(c) either of the above
(d) none of the above
Ans: a
(a) to withstand the high voltage drop due to line surge produced by the shunting capacitance of the end turns
(b) to absorb the line surge voltage and save the winding of transformer from damage
(c) to reflect the line surge and save the winding of a transformer from damage
(d) none of the above
Ans: a
(a) eddy current loss will decrease
(b) eddy current loss will increase
(c) eddy current loss will remain unchanged
(d) none of the above
Ans: c
(a) friction and windage losses
(b) magnetic losses
(c) hysteresis and eddy current losses
(d) copper losses
Ans: a
(a) hysteresis and eddy current losses
(b) friction and windage losses
(c) copper losses
(d) none of the above
Ans: a
(a) Its secondary current is 5 A
(b) Its secondary voltage is 400 V
(c) Its rating is 2 kVA
(d) Its secondary current is 20 A
(e) It is a step-up transformer
Ans: d
(a) avoids core saturation and high voltage induction
(b) is safe to human beings
(c) protects the primary circuit
(d) none of the above
Ans: a
(a) zero
(b) 10 Q
(c) 1000 Q
(d) infinity
Ans: d
(a) output voltage fluctuation from no load to full load is least
(b) output voltage fluctuation with power factor is least
(c) difference between primary and secondary voltage is least
(d) difference between primary and secondary voltage is maximum
Ans: a
(a) 0.8 leading power factor
(b) 0.8 lagging power factor
(c) zero power factor
(d) unity power factor
Ans: d
(a) Overfluxing protection
(b) Buchholz relay
(c) Overcurrent protection
(d) All of the above
Ans: b
(a) Horn gaps
(b) Thermal overload relays
(c) Breather
(d) Conservator
Ans: a
(a) short-circuit test
(b) back-to-back test
(c) open circuit test
(d) any of the above
Ans: b
(a) Cellulose
(b) Asbestos
(c) Mica
(d) Glass fibre
Ans: c
119. Which of the following parts of a transformer is visible from outside ?
(a) Bushings
(b) Core
(c) Primary winding
(d) Secondary winding
Ans: a
(a) zoom
(b) hum
(c) ringing
(d) buzz
Ans: b
(a) Core loss
(b) Friction loss
(c) Eddy current loss
(d) Hysteresis loss
Ans: b
(a) poor insulation
(b) Overload
(c) loose connections
(d) Core saturation
Ans: d
(a) core
(b) windings
(c) tank
(d) any of the above
Ans: b
(a) load changes
(b) oil in the transformer
(c) magnetostriction
(d) mechanical vibrations
Ans: c
(a) temperature rise
(b) dielectric strength of oil
(c) voltage ratio
(d) copper loss
Ans: c
(a) copper loss becomes high in proportion to the output
(b) iron loss is increased considerably
(c) voltage drop both in primary and secondary becomes large
(d) secondary output is much less as compared to primary input
Ans: a
(a) insulation resistance
(b) copper loss
(c) core loss
(d) total loss
(e) efficiency
(f) none of the above
Ans: c
(a) core loss
(b) copper loss
(c) efficiency
(d) magnetising current
(e) magnetising current and loss
Ans: e
(a) primary turns to secondary turns
(b) secondary current to primary current
(c) secondary induced e.m.f. to primary induced e.m.f.
(d) secondary terminal voltage to primary applied voltage
Ans: c
(a) iron core
(b) copper winding
(c) winding insulation
(d) frame or case
(e) transformer tank
Ans: c
(a) its power factor will deteriorate
(b) its power factor will increase
(c) its power factor will remain unaffected
(d) its power factor will be zero
Ans: a
(a) approximately equal to one
(b) less than one
(c) great than one
(d) none of the above
Ans: a
(a) unity
(b) lagging
(c) leading
(d) zero
Ans: c
(a) less than 15 A
(b) more than 15 A
(c) 15 A
(d) none of the above
Ans: a
(a) about the same
(6) much smaller
(c) much higher
(d) somewhat smaller
(e) none of the above
Ans: c